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3.14r^2=2110.08
We move all terms to the left:
3.14r^2-(2110.08)=0
We add all the numbers together, and all the variables
3.14r^2-2110.08=0
a = 3.14; b = 0; c = -2110.08;
Δ = b2-4ac
Δ = 02-4·3.14·(-2110.08)
Δ = 26502.6048
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{26502.6048}}{2*3.14}=\frac{0-\sqrt{26502.6048}}{6.28} =-\frac{\sqrt{}}{6.28} $$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{26502.6048}}{2*3.14}=\frac{0+\sqrt{26502.6048}}{6.28} =\frac{\sqrt{}}{6.28} $
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